Question

bryson has twelve cards. each card has a different number from 1 to 12 on it. he chooses a card at random

how likely is it for bryson to choose an odd number?
unlikely
as likely as not
likely
certain

how likely is it for Bryson to choose a number greater than 4?

Answer 1

To determine the likelihood of Bryson choosing an odd number and a number greater than 4, we can analyze his cards.

1. **Choosing an odd number:**
- The cards are numbered from 1 to 12.
- The odd numbers in this range are: 1, 3, 5, 7, 9, 11.
- There are 6 odd numbers.
- Total cards = 12.
- The probability of choosing an odd number = Number of odd cards / Total cards = 6/12 = 1/2.

Since the probability is 1/2, we can say this outcome is **as likely as not**.

2. **Choosing a number greater than 4:**
- The numbers greater than 4 are: 5, 6, 7, 8, 9, 10, 11, 12.
- There are 8 numbers greater than 4.
- Total cards = 12.
- The probability of choosing a number greater than 4 = Number of cards greater than 4 / Total cards = 8/12 = 2/3.

Since the probability is 2/3, this outcome is **likely**.

In summary:
- Probability of choosing an odd number: **as likely as not**
- Probability of choosing a number greater than 4: **likely**