Asked by kabelo
consider a simple harmonic oscillation with m=0.5kg, k=10N/m and amplitude A=3cm.WHat is the total energy of the oscillation,what is the maximum speed,what is the kinetic energy?
Answers
Answered by
Damon
w = 2 pi f = sqrt (k/m)
A = 3 cm use .03 m
let x = A sin w t
then v = A w cos wt
v is maximum when cos = 1 (or -1)
so V = v maximum = Aw
that is max speed
At that point of maximum speed for example when x = 0 and t = 0 the potential energy being (1/2) k x^2 is also 0
Therefore the total energy = kinetic energy = (1/2)mV^2
A = 3 cm use .03 m
let x = A sin w t
then v = A w cos wt
v is maximum when cos = 1 (or -1)
so V = v maximum = Aw
that is max speed
At that point of maximum speed for example when x = 0 and t = 0 the potential energy being (1/2) k x^2 is also 0
Therefore the total energy = kinetic energy = (1/2)mV^2
Answered by
taera
25 J
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