Asked by Anonymous
A simple harmonic oscillator executes motion whose amplitude is .20 m and it completes 60 oscillations in 2 minutes Calculate its time period and angular frequency
Answers
Answered by
Henry
a. T = 2min/60cycles = 120s/60cycles = 2s/cycles
b. F = 1/T = 1cycle/2s. = 0.50 cycles/s.
= 0.50 Hz.
b. F = 1/T = 1cycle/2s. = 0.50 cycles/s.
= 0.50 Hz.
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