A simple harmonic oscillator executes motion whose amplitude is .20 m and it completes 60 oscillations in 2 minutes Calculate its time period and angular frequency

Answer 1

a. T = 2min/60cycles = 120s/60cycles = 2s/cycles

b. F = 1/T = 1cycle/2s. = 0.50 cycles/s.
= 0.50 Hz.