Question

A simple harmonic oscillator's velocity is given by vy(t) = (0.86 m/s)sin(11t − 5.55). Find the oscillator's position, velocity, and acceleration at each of the following times. (Include the sign of the value in your answer) a) t = 0s
b) t = 0.5s c) t = 2s

Answer 1

dv/dt=acceleration
INt dv = -cos(11t-5.55) (.86/11)= position

plug in t, and you have it.