Asked by Aleena
A simple harmonic oscillator has spring constant = 8.8N/m , amplitude = 11cm , and maximum speed 4.6m/s .
what is the speed when x=6cm?
what is the speed when x=6cm?
Answers
Answered by
bobpursley
total energy= 1/2 K .11^2
now, when .06 cm, then PE = 1/2 k * .06^2 and KE then will be
KE= 1/2 K * .0121-1/2 m v^2
what is m? well, max KE=max Pe
1/2 m 4.6^2=1/2 K *.0121 solve for m
now solve for v in the KE equation.
now, when .06 cm, then PE = 1/2 k * .06^2 and KE then will be
KE= 1/2 K * .0121-1/2 m v^2
what is m? well, max KE=max Pe
1/2 m 4.6^2=1/2 K *.0121 solve for m
now solve for v in the KE equation.
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