Question

A crate sliding down a ramp reaches the bottom of the ramp and slides across a flat floor. At the instant shown, the crate has a speed of v= 8.90 m/s. The crate comes to a stop after a distance x= 13.0m . What is the coefficient of kinetic friction between the crate and the floor?

Ok so I drew the free body diagram and everything and kinetic friction = a/g

I know g= 9.81
how do i solve for acceleration? do i assume initial velocity is zero.

because I would have used the equation
v^2=iniv^2+2a(x)
acceleration is 3.05 m/s^2

then friction=3.05/9.81, correct?
μ<sub>k</sub>=3.05/9.81 is correct.

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