Asked by Mercedes

A 435 N box is sliding down a 40 degree incline. If the acceleration of the box is 0.250 m/s^2, what is the force of friction on the box?

15 years ago

Answered by bobpursley

force down the plane due to gravity: 435Sin40

435Sin40-forcefriction=435/g * .250

solve for force of friction.

15 years ago

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