Asked by danny

A 100-kg crate, sliding on the floor, is brought to a stop by a 25-n force. What is the deceleration of the crate?
Answered by bobpursley
F=ma

a=F/m
Answered by hanan kalid
the answer is 2500
Answered by hanan kalid
the answer is 98
Answered by hanan kalid

A 100-kg crate, sliding on the floor, is brought to a stop by a 25-n force. What is the deceleration of the crate?

and the answer is 2500
Answered by pk
since acceleration = Net force/ mass,
plug in 25 N for force and 100 kg for mass

you will get 0.25 m/s^2
Answered by pk
actually, 0.25 with sig figs is 0.3 m/s^2, which is the correct answer.
Answered by Anonymous
i dont understand how this is to help me??????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
Answered by Anonymous
It would definitely be 0.25 m/s, because you are finding the deceleration which is really another way to say something accelerates, and of something is accelerating we use the formula A=f/m. Divide 25 by 100 and you get 0.25
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