Asked by Amanda and Leah
Pete slides a crate up a ramp at an angle of 20 degrees by exerting a 244 N force parallel to the ramp. The crate moves at a constant speed. The coefficient of friction is 0.19. How much work did Pete do when the crate was raised a vertical distance of 2.39 m? Answer in units of J
Answers
Answered by
drwls
Force * distance = 244*(2.39/sin20)
= 1705 J
You do not need to know the coefficient of friction.
= 1705 J
You do not need to know the coefficient of friction.
Answered by
Anonymous
Pete slides a crate up a ramp at an angle of
35◦ by exerting a 179 N force parallel to the
ramp. The crate moves at a constant speed.
The coefficient of friction is 0.21.
How much work did Pete do when the crate
was raised a vertical distance of 1.83 m?
Answer in units of J.
35◦ by exerting a 179 N force parallel to the
ramp. The crate moves at a constant speed.
The coefficient of friction is 0.21.
How much work did Pete do when the crate
was raised a vertical distance of 1.83 m?
Answer in units of J.
Answered by
Jared
Drwls is certainly not correct.
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