Ask a New Question

Asked by kwack

Find the equation of the tangent line to the curve y=5xcosx at the point (pi,–5pi).

The equation of this tangent line can be written in the form y=mx+b where

m=

and b=
15 years ago

Answers

Answered by bobpursley
y=5x cos x
y'=slope m= 5cosx-5xsinx at x=pi
y'=m=-5

line equation: y= -5x+b
now to find b, you know the point(PI,-5PI) is on it, so

-5pi--5PI+b so b=0
15 years ago

Related Questions

Find the equation of the tangent and normal line of the equation: f(x) = √x^2 - 1, at x = 1 Show... find the equation of the tangent to the curve y=x^2-1/3x at x=2 Find the equation of the tangent to 3x^2 +4y^2 =7 at P(1, 1). (pls provide step by step, use impl... Find the equation of the tangent line to the graph of y=3^x−2 at x = 1. Give your answer in slope-in... Find the equation of the tangent line at the point on the graph of the equation y^2-xy-12=0, where x... Find the equation of the tangent to the following circles at the given coordinates: 1) x^2 +y^2 = 2... Find the equation of the tangent line for the curve x^2 + y^2 = 4 at the point (2, 0)
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use