Asked by yoyoma

A runner accelerates to a velocity of 5.28 m/s due west in 3 s. His average acceleration is 0.635 m/s2, also directed due west. What was his velocity when he began accelerating?
Answered by Anonymous
Multiply 0.635 m/s2 by 3 s to get the velocity change: 1.905 m/s

You can do the rest.
Answered by drwls
V2 - V1 = 0.635*3 = 1.905 m/s

V2 = 5.28 m/s

Solve for V1.

V1 = 5.28 - 1.905 = ? m/s
There are no AI answers yet. The ability to request AI answers is coming soon!