Question
what is the instantaneous velocity of a free falling object 10s after it is released from a postion of rest?
what is its average velocity during this 10s interval?
how far will it fall during this time?
what is its average velocity during this 10s interval?
how far will it fall during this time?
Answers
for constant acceleration:
V = Vo + a t
so for a = g = -9.8 m/s^2
V = 0 - 9.8 t = -98 meters/second
average = (Vo+V)/2 = (0-98)/2 = 49 m/s
distance = average velocity * time = 490 meters
V = Vo + a t
so for a = g = -9.8 m/s^2
V = 0 - 9.8 t = -98 meters/second
average = (Vo+V)/2 = (0-98)/2 = 49 m/s
distance = average velocity * time = 490 meters
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