Asked by Hillary
what is the instantaneous velocity of a free falling object 10s after it is released from a postion of rest?
what is its average velocity during this 10s interval?
how far will it fall during this time?
what is its average velocity during this 10s interval?
how far will it fall during this time?
Answers
Answered by
Damon
for constant acceleration:
V = Vo + a t
so for a = g = -9.8 m/s^2
V = 0 - 9.8 t = -98 meters/second
average = (Vo+V)/2 = (0-98)/2 = 49 m/s
distance = average velocity * time = 490 meters
V = Vo + a t
so for a = g = -9.8 m/s^2
V = 0 - 9.8 t = -98 meters/second
average = (Vo+V)/2 = (0-98)/2 = 49 m/s
distance = average velocity * time = 490 meters
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.