Asked by Anonymous
What is the instantaneous velocity of a freely falling object 10s after it is released from rest? What is its average velocity during this 10s interval? How far will it fall during this time?
For the average speed I got 50m/s nd for the last one I got 500m
is this right? how do I do the first one? please help
For the average speed I got 50m/s nd for the last one I got 500m
is this right? how do I do the first one? please help
Answers
Answered by
drwls
If you use the correct value for g, 9.8 m/s^2, you will find that the instantaneous velocity after 10 seconds is 98 m/s. The average velocity is half that.
The distance travelled is time x (avg. velocity) = 490 m
You method of soloution is correct, you just used a different value of g that you may have been told to use.
Thanks for showing your work. I wish more students would do that.
The distance travelled is time x (avg. velocity) = 490 m
You method of soloution is correct, you just used a different value of g that you may have been told to use.
Thanks for showing your work. I wish more students would do that.
Answered by
Anonymous
thank you
my teacher just told me to round it up to 10m/s^2
my teacher just told me to round it up to 10m/s^2
Answered by
aa
What is the instantaneous velocity of a falling object 5s after it is released from rest? What it its average velocity during this 5s–interval? How far will it fall during this time?
Answered by
Heav
Given:
T=10s
G= 10m/s
V=?
V=(10 • 10)
V= 100 m/s
Average Velocity= 100/2
So, = 50m/s
Distance= 1/2(10)(10)=50 m
Yay<3
T=10s
G= 10m/s
V=?
V=(10 • 10)
V= 100 m/s
Average Velocity= 100/2
So, = 50m/s
Distance= 1/2(10)(10)=50 m
Yay<3
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