Asked by Sandy
Runner A speed 1km/hour
Runner B speed 2km/hour
They start of at the same point at the oval.In a lap that is 500m, how many times will they meet at the starting point after 10 hours.
I managed to get the LCM for runner A,B using the time taken to complete 1 lap
A=1/2 hrs, B=1/4 hours
=>LCM is 1/2 hrs
In 10 hrs would they have meet 10/(1/2)=20 times at the starting point?
I was told that it will be 19 times,but not sure why!thanks for your help
Runner B speed 2km/hour
They start of at the same point at the oval.In a lap that is 500m, how many times will they meet at the starting point after 10 hours.
I managed to get the LCM for runner A,B using the time taken to complete 1 lap
A=1/2 hrs, B=1/4 hours
=>LCM is 1/2 hrs
In 10 hrs would they have meet 10/(1/2)=20 times at the starting point?
I was told that it will be 19 times,but not sure why!thanks for your help
Answers
Answered by
Steve
Hmmm. Looks like 20 to me, too. There aren't any fractional laps to worry about.
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