Asked by tony
A 82 kg runner with a speed of 5.6 m/s makes a sharp turn with a radius of 1.1 m to avoid a collision. What is the magnitude of the frictional force (in N) the ground exerts on the runner during the turn?
Answers
Answered by
Chanz
mv^2/r = Ff
Plug. Chug.
Plug. Chug.
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