Asked by Anonymous
A 70.0-kg runner has a speed of 5.90 m/s at one instant during a long-distance event.What is the runner's kinetic energy at this instant? If he doubles his speed to reach the finish line, by what factor does his kinetic energy change?
Answers
Answered by
Henry
1. KE=0.5mV^2=0.5 * 70 * (5.90)^2=1218J
2. 2^2 = 4 = The factor by which the KE
is incrased.
2. 2^2 = 4 = The factor by which the KE
is incrased.
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