Asked by Juan Carlos
A ball thrown straight up takes 5.80 seconds to go up and come back down to its starting point. Neglecting air resistance, how high (in m) does it go?
Answers
Answered by
bobpursley
It reaches its peak at time 5.80/2 seconds
So then if falls...starting at the top with zero velocity.
h=1/2 g t^2 find h, using t=2.90seconds
So then if falls...starting at the top with zero velocity.
h=1/2 g t^2 find h, using t=2.90seconds
Answered by
bob
41.209
Answered by
porquillo
14
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