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A ball is thrown straight up from the top of a building 144 ft tall with an initial velocity of 48 ft per second. The height
s(t) (in feet)
of the ball from the ground, at time t (in seconds), is given by
s(t) = 144 + 48t − 16t2.
Find the maximum height attained by the ball.
4 years ago

Answers

oobleck
as with all quadratics (ax^2+bx+c), the vertex is at x = -b/2a
4 years ago

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