Asked by Angel45
A ball is thrown straight up from the top of a building 144 ft tall with an initial velocity of 48 ft per second. The height
s(t) (in feet)
of the ball from the ground, at time t (in seconds), is given by
s(t) = 144 + 48t − 16t2.
Find the maximum height attained by the ball.
s(t) (in feet)
of the ball from the ground, at time t (in seconds), is given by
s(t) = 144 + 48t − 16t2.
Find the maximum height attained by the ball.
Answers
Answered by
oobleck
as with all quadratics (ax^2+bx+c), the vertex is at x = -b/2a
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.