Asked by Jonah
If a ball is thrown straight up from the top of a building that is 407 feet high, the position in feet
above the ground is given by the function s(t) = -16t^2 + 75t + 407 where t is the number of
seconds elapsed.
a. How high is the projectile after 3 seconds?
b. How long will it take for the ball to reach a height of 450 feet above the ground?
above the ground is given by the function s(t) = -16t^2 + 75t + 407 where t is the number of
seconds elapsed.
a. How high is the projectile after 3 seconds?
b. How long will it take for the ball to reach a height of 450 feet above the ground?
Answers
Answered by
Steve
man, they gave you the function. Just plug in the numbers to find your answers.
(a) s(3) = -16*3^2 + 75*3 + 407
(b) solve s(t) = 450
(a) s(3) = -16*3^2 + 75*3 + 407
(b) solve s(t) = 450
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