Asked by Anonymous
A ball is thrown straight up with an intial velocity of 85 ft/s. At what times will it have a height of 200 ft?
Answers
Answered by
bobpursley
h=vi*t-1/2 g t^2
200=85*t-1/2 *33*t62 solve for time(s) t. use the quadratic formula.
200=85*t-1/2 *33*t62 solve for time(s) t. use the quadratic formula.
Answered by
drwls
When 85 t - (g/2) t^2 = 200
g = 32.2 ft/s^2
Do the math. There will be two answers.
g = 32.2 ft/s^2
Do the math. There will be two answers.
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