Asked by Reagan
A ball is thrown straight up from the top of a building 148 ft. tall with an initial velocity of 72 ft per second. The distance
s(t) (in feet)
of the ball from the ground is given by
s(t) = 148 + 72t − 16t2.
Find the maximum height attained by the ball.
s(t) (in feet)
of the ball from the ground is given by
s(t) = 148 + 72t − 16t2.
Find the maximum height attained by the ball.
Answers
Answered by
Steve
well, the vertex is at t = -b/2a = 72/32 = 9/4
So, find s(9/4)
So, find s(9/4)
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