Question
A ball is thrown from straight up from a height of 1.25 meters above the ground with an initial velocity of 30 meters per second. What is the max height? When does the ball reach its max height?
Answers
Answered by
oobleck
v^2 = 2gh
so plug in your numbers to find h
or, the height is
y = 1.25 + 30t - 4.9t^2
max height is at the vertex, which is when t = -n/2a = 30/9.8
so plug in your numbers to find h
or, the height is
y = 1.25 + 30t - 4.9t^2
max height is at the vertex, which is when t = -n/2a = 30/9.8
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