Asked by Jason
A ball is thrown straight up from the top of a 200 foot building with an initial velocity of 40feet/second. acceleration due to gravity is -32feet/second.
a) find a formula for the height of the ball at time t.
b) how high does the ball rise before it begins to fall
c) when does it hit the ground(assuming it does not fall back onto the roof of the building)
a) find a formula for the height of the ball at time t.
b) how high does the ball rise before it begins to fall
c) when does it hit the ground(assuming it does not fall back onto the roof of the building)
Answers
Answered by
Steve
h(t) = 200 + 40t - 16t^2
now work your magic on (b) and (c)
now work your magic on (b) and (c)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.