Asked by syida
A ball is thrown straight up and returns to its starting point in 5 second. What is the initial speed of the ball?
Answers
Answered by
Henry
t(up) = 5/2 = 2.5s.
Vf = Vo + gt,
Vo=Vf - gt = 0 - (-9.8)*2.5 = 24.5 m/s.
Vf = Vo + gt,
Vo=Vf - gt = 0 - (-9.8)*2.5 = 24.5 m/s.
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