Asked by Elizabeth

A ball is thrown straight up at an initial speed of 24 m/s. How long did it take to reach maximum height? How high did it rise before falling again?
I am confused on how to attempt this problem. Please provide me with some guidance:)
Answered by Damon
v = Vi - g t
0 = 24 - 9.81 t
t = 24/9.81

h = 24 t -4.9 t^2

Answered by Elizabeth
I get it now! I was confused about the final velocity. So, is the final velocity 0 m/s because that is when it hit the ground?
Answered by Damon
No, 0 at max height. It stops at the top, then falls
Answered by Elizabeth
Oh...So it pauses for a second and then falls to the ground!
Answered by Elizabeth
Do you mind if I verify a couple more questions? My physics background is not very strong:(
Answered by Damon
go ahead and post them separately above.
Answered by Elizabeth
Thanks!
Answered by Damon
well, it pauses for in ten zillionth of a second. In other words the velocity goes from upward to downward so it goes through zero :)
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