Asked by Rhea Mae
A ball is thrown straight up that it reaches a max height of 30 meter. How long did it take the ball to go up? How fast was it going when it was 10 meter high from the ground?
Answers
Answered by
Damon
(1/2) m Vi^2 at bottom = m g h at top
Vi^2 = 2 g h = 2 * 9.8 * 30
Vi = 24.2 m/s
v = Vi - g t
0 = 24.2 - 9.8 t
t = 2.47 s
(1/2) m Vi^2 = (1/2) m v^2 + m g (10)
24.2^2 = v^2 + 98*2
v = 19.7 m/s
Vi^2 = 2 g h = 2 * 9.8 * 30
Vi = 24.2 m/s
v = Vi - g t
0 = 24.2 - 9.8 t
t = 2.47 s
(1/2) m Vi^2 = (1/2) m v^2 + m g (10)
24.2^2 = v^2 + 98*2
v = 19.7 m/s
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