A ball is thrown straight up from the ground at 10m/s, and simultaneously a ball is thrown straight down a 10m-high ledge at 10m/s. At what height do the two balls pass?

1 answer

H=10t-5t^2 10-H=10t+5t^2 10-10t+5t^2=10t+5t^2 20t=10 t=0.5secs H=10(0.5)-5(0.25)=3.75m