Asked by Tom
A ball is thrown straight up from the edge of the roof of a 60.0 m tall building. If a second ball is
dropped from the roof 2.0 s later what must the initial velocity of the first ball be if both are to reach
the ground at the same time?
dropped from the roof 2.0 s later what must the initial velocity of the first ball be if both are to reach
the ground at the same time?
Answers
Answered by
Steve
The second ball hits when
60-4.9(t-2)^2 = 0,
t = 5.5
v = 19.6(1 - 1/5.5) = 10.036 m/s
So, you want v where
60 + 5.5v - 4.9*5.5^2 = 0
v = 16.04 m/s
check:
60-4.9(t-2)^2 = 0,
t = 5.5
v = 19.6(1 - 1/5.5) = 10.036 m/s
So, you want v where
60 + 5.5v - 4.9*5.5^2 = 0
v = 16.04 m/s
check:
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