Asked by Kayla
How do I find the extreme values for the function y=sinx+cosx on the interval 0<x<2(pi)
Answers
Answered by
jai
get the derivative to get the maximum/minimum:
y = sinx + cosx
y' = 0 = cosx - sinx
cos x = sin x
x=pi/4 *the value of x in which y is max
x=-(pi/4) *the value of x in which y is min
you can actually check this by graphing the equation,,
so there,, =)
y = sinx + cosx
y' = 0 = cosx - sinx
cos x = sin x
x=pi/4 *the value of x in which y is max
x=-(pi/4) *the value of x in which y is min
you can actually check this by graphing the equation,,
so there,, =)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.