Asked by dt
find the extreme values of the function and where they occur
y=x^3+x^2-8x+5
y=x^3+x^2-8x+5
Answers
Answered by
Damon
dy/dx = 0 = 3 x^2 + 2 x - 8
(3x-4)(x+2) = 0
x = 4/3 or x = -2
now go back and find y for each x
(3x-4)(x+2) = 0
x = 4/3 or x = -2
now go back and find y for each x
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