Question

The glass, weighing 6.0 g, experienced a temperature shift from 20.0°C to 45.0°C upon absorbing 550 J of heat. What is the specific heat of this glass?

(1 point)
Responses

0.27 J/g °C
0.27 J/g °C

130 J/g °C
130 J/g °C

3.7 J/g °C
3.7 J/g °C

2300 J/g °C

Answer 1

To find the specific heat \( c \) of the glass, we can use the formula for heat transfer:

\[
q = mc\Delta T
\]

Where:
- \( q \) is the heat absorbed (in Joules),
- \( m \) is the mass (in grams),
- \( c \) is the specific heat (in J/g °C),
- \( \Delta T \) is the change in temperature (in °C).

Given:
- \( q = 550 \, \text{J} \)
- \( m = 6.0 \, \text{g} \)
- Initial temperature \( T_i = 20.0 \, \text{°C} \)
- Final temperature \( T_f = 45.0 \, \text{°C} \)

Now, we first calculate \( \Delta T \):

\[
\Delta T = T_f - T_i = 45.0 \, \text{°C} - 20.0 \, \text{°C} = 25.0 \, \text{°C}
\]

Next, plug the values into the heat transfer equation:

\[
550 \, \text{J} = 6.0 \, \text{g} \cdot c \cdot 25.0 \, \text{°C}
\]

Now we solve for \( c \):

\[
550 \, \text{J} = 150.0 \, \text{g °C} \cdot c
\]

\[
c = \frac{550 \, \text{J}}{150.0 \, \text{g °C}}
\]

Calculating \( c \):

\[
c = \frac{550}{150.0} \approx 3.67 \, \text{J/g °C}
\]

Therefore, the specific heat of the glass is approximately \( 3.7 \, \text{J/g °C} \).

The correct response is:

**3.7 J/g °C**