Question

The glass, weighing 6.0 g, experienced a temperature shift from 20.0°C to 45.0°C upon absorbing 550 J of heat. What is the specific heat of this glass?

(1 point)

3.7 J/g "C

130 J/g "C

0.27 J/g "C

2300 J/g "C

Answer 1

To calculate the specific heat (\(c\)) of the glass, we can use the formula:

\[
c = \frac{q}{m \cdot \Delta T}
\]

where:
- \(q\) is the amount of heat absorbed (in joules),
- \(m\) is the mass of the substance (in grams),
- \(\Delta T\) is the change in temperature (in °C).

Given values:
- \(q = 550 \, J\)
- \(m = 6.0 \, g\)
- Initial temperature (\(T_i\)) = 20.0°C
- Final temperature (\(T_f\)) = 45.0°C

First, we need to calculate the change in temperature (\(\Delta T\)):

\[
\Delta T = T_f - T_i = 45.0°C - 20.0°C = 25.0°C
\]

Now, we can substitute the values into the specific heat formula:

\[
c = \frac{550 \, J}{6.0 \, g \cdot 25.0°C}
\]

Calculating the denominator:

\[
6.0 \, g \cdot 25.0°C = 150.0 \, g \cdot °C
\]

Now, substituting this back into the equation for \(c\):

\[
c = \frac{550 \, J}{150.0 \, g \cdot °C} \approx 3.67 \, J/g \cdot °C
\]

Rounding to two decimal places gives us:

\[
c \approx 3.7 \, J/g \cdot °C
\]

Thus, the specific heat of the glass is **3.7 J/g °C**.