Question

A glass piece weighing 50 grams, possessing a specific heat of 0.84 J/g°C, undergoes heating from 35°C to 46°C. What is the total amount of heat added to the glass?
A. 193 J
B. 462 J
C. 11 J
D. 1470 J

Answer 1

To find the total amount of heat added to the glass, you can use the formula:

\[ Q = mc\Delta T \]

where:
- \( Q \) = heat added (in joules)
- \( m \) = mass of the substance (in grams)
- \( c \) = specific heat capacity (in J/g°C)
- \( \Delta T \) = change in temperature (in °C)

Given:
- \( m = 50 \) g
- \( c = 0.84 \) J/g°C
- Initial temperature = 35°C
- Final temperature = 46°C

First, calculate the change in temperature \( \Delta T \):

\[ \Delta T = \text{Final temperature} - \text{Initial temperature} = 46°C - 35°C = 11°C \]

Now, plug the values into the heat formula:

\[ Q = mc\Delta T \]
\[ Q = 50 \, \text{g} \times 0.84 \, \text{J/g°C} \times 11°C \]

Now calculate:

\[ Q = 50 \times 0.84 \times 11 \]
\[ Q = 50 \times 9.24 \]
\[ Q = 462 \, \text{J} \]

Therefore, the total amount of heat added to the glass is \( \boxed{462 \, \text{J}} \).