Question

A glass piece weighing 50 grams, possessing a specific heat of 0.84 J/g°C, undergoes heating from 35°C to 46°C. What is the total amount of heat added to the glass? (1 point)

462J

193J

1470 J
11 J

Answer 1

To calculate the total amount of heat added to the glass, you can use the formula:

\[
Q = mc\Delta T
\]

where:
- \( Q \) is the heat added (in joules),
- \( m \) is the mass (in grams),
- \( c \) is the specific heat capacity (in J/g°C),
- \( \Delta T \) is the change in temperature (in °C).

Given:
- Mass \( m = 50 \) grams,
- Specific heat \( c = 0.84 \) J/g°C,
- Initial temperature \( T_i = 35°C \),
- Final temperature \( T_f = 46°C \).

First, calculate the change in temperature (\( \Delta T \)):
\[
\Delta T = T_f - T_i = 46°C - 35°C = 11°C
\]

Now, plug the values into the formula:
\[
Q = (50 \, \text{g}) \times (0.84 \, \text{J/g°C}) \times (11 \, \text{°C})
\]

Calculating this:
\[
Q = 50 \times 0.84 \times 11
\]
\[
Q = 50 \times 9.24
\]
\[
Q = 462 \, \text{J}
\]

Thus, the total amount of heat added to the glass is **462 J**.