Asked by Anonymous
A 15.0kg bix is released on a 32degree inclined and accelerates down the inclined at 0.30m/s^2. find the friction force impeding its motion.
Answers
Answered by
drwls
The NET force acting down the plane is
F = M*a= 4.5 N
The gravity force component down the incline is
M g sin 32 = 77.9 N
The difference between those two numbers is the friction force.
F = M*a= 4.5 N
The gravity force component down the incline is
M g sin 32 = 77.9 N
The difference between those two numbers is the friction force.
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