Asked by Raj
A sample of solid monoprotic acid with molar mass equal to 137.9 g/mol was titrated with 0.1879 M sodium hydroxide solution. Calculate the mass in grams of acid to be used if the volume of NaOH to be used is 25 mL.
Answers
Answered by
DrBob222
L(NaOH) x M(NaOH) = mols(NaOH)
Mols NaOH = mols acid
g acid/molar mass acid = mols acid
solve for g acid.
Post your work if you get stuck.
Mols NaOH = mols acid
g acid/molar mass acid = mols acid
solve for g acid.
Post your work if you get stuck.
Answered by
Fai
0.1879M x 0.025L = 4.6975 mols
4.6975 x 137.9 = 647.78 changes 0.647gm
I am not sure answer who tells me the right. Pls help
4.6975 x 137.9 = 647.78 changes 0.647gm
I am not sure answer who tells me the right. Pls help
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