A sample of solid monoprotic acid with molar mass equal to 169.7 g/mol was titrated with 0.1599 M sodium hydroxide solution. Calculate the mass in grams of acid to be used if the volume of NaOH to be used is 25 mL.
Is the solution correct?:
moles NaOH = 0.1599 x 0.025=3.998x10^-3
moles H+ = moles NaOH (from equation) = 3.998x10^-3
mass H+ = moles x molar mass= 3.998x10^-3 x 169.7 = 0.6789g
1 answer
I didn't check the math, but the procedure is correct.
2 answers