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Asked by TROUBLED

A 3.664 g sample of monoprotic acid was dissolved in water and required 20.27 mL of a 0.1578 M NaOH solution for neutralization . Calculate the molar mass of the acid
13 years ago

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Answered by bobpursley
moles acid=moles base
3.664/molmass=1.578*.02027
solve for molemass
13 years ago

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