Question
determine the nature of the solutions of the equation. Two real solutions, two imaginary solutions, or one real solution.
2t^2-4t=0
2t^2-4t=0
Answers
Tony
Here, discriminant = (-4)^2 = 16
Hence, discriminant is positive and greater than 0
Therefore, there are two real solutions of the given equation
Hence, discriminant is positive and greater than 0
Therefore, there are two real solutions of the given equation