Asked by Saphina AlMatary
Determine the nature of the roots of the following quadratic equations:
(a) 3x^2 - 6x + 7 = 0
(b) 3x^2 + 6x - 7 = 0
(c) -5x^2- x/5 = 0
(d) 4x^2 - 28 49
----x + ----- = 0
3 9
(a) 3x^2 - 6x + 7 = 0
(b) 3x^2 + 6x - 7 = 0
(c) -5x^2- x/5 = 0
(d) 4x^2 - 28 49
----x + ----- = 0
3 9
Answers
Answered by
Damon
b^2-4ac says it all
in (a) for example
36-4(21) is negative so sqrt of negative in sollution so complex roots
(b) 36 + 4(21) is + so real roots
(c) x^2 + x/25 = 0
x(x+1/25) = 0
x = 0 or x = -1/25
(d) ?
in (a) for example
36-4(21) is negative so sqrt of negative in sollution so complex roots
(b) 36 + 4(21) is + so real roots
(c) x^2 + x/25 = 0
x(x+1/25) = 0
x = 0 or x = -1/25
(d) ?
Answered by
Reiny
check in your text or in your notes what properties are needed to investigate the nature of the roots.
hint: it has to do with the determinant.
btw. - I can't make your your last equation.
hint: it has to do with the determinant.
btw. - I can't make your your last equation.
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