Asked by Ashutosh
Determine the nature of conic
a) x<2 -4xy + 10 <2+2y-5 = 0
b) x<2 -4xy + 3x + 25y -6= 0
a) x<2 -4xy + 10 <2+2y-5 = 0
b) x<2 -4xy + 3x + 25y -6= 0
Answers
Answered by
oobleck
If by x<2 you mean x^2 (x-squared) then
(a) still garbled
(b) x^2 - 4xy + 3x + 25y - 6 = 0
(x + 3/2)^2 - 4xy + 25y = 33/4
is an hyperbola rotated through
tan2θ = -4
θ ≈ 52°
(a) still garbled
(b) x^2 - 4xy + 3x + 25y - 6 = 0
(x + 3/2)^2 - 4xy + 25y = 33/4
is an hyperbola rotated through
tan2θ = -4
θ ≈ 52°
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