Asked by Aaron
A conic section has the equation x2 + y2 + 10x + 8y = 40. Determine the following: type of conic, domain and range, axes of symmetry, and center. Show your work.
Answers
Answered by
Steve
x^2 + y^2 + 10x + 8y = 40
x^2+10x + y^2+8y = 40
x^2+10x+25 + y^2+8y+16 = 40+25+16
(x+5)^2 + (y+4)^2 = 81
That help?
x^2+10x + y^2+8y = 40
x^2+10x+25 + y^2+8y+16 = 40+25+16
(x+5)^2 + (y+4)^2 = 81
That help?
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