Asked by saad
Explain which conic section this equation and explain how to solve it:
12x^2-18y^2-18x-12y+12=0
12x^2-18y^2-18x-12y+12=0
Answers
Answered by
drwls
When the x^2 and y^2 terms have opposite signs, you have a hyperbola. For the location and the asymptotes, try completing the squares of the x and y polynomials.
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