Asked by nano
How much heat in kilojoules is evolved in converting 1.00 mol of steam at 145 Celsius to ice at -50 Celsius?
Please, all particular steps and conversions between mole and grams of steam, H2O and ice. Thanks!
Please, all particular steps and conversions between mole and grams of steam, H2O and ice. Thanks!
Answers
Answered by
DrBob222
q1 = heat evolved in moving steam from 145 to 100.
q1 = mass steam x specific heat steam x (Tfinal-Tinital) where Tfinal is 100 and Tinitial is 145.
q2 = heat evolved when steam at 100 C condenses to liquid at 100 C.
q2 = mass x heat vaporization
q3 = heat evolved in moving water from 100 C to zero.
q3 = mass water x specific heat water x (Tfinal-Tinitial) where T final is zero and Tinitial is 100.
q4 = heat evolved on freezing water at zero to ice at zero.
q4 = mass water x heat fusion.
q5 = heat evolved in moving ice from zero to -50.
q5 = mass ice x specific heat ice x (Tfinal-Tinitial) where Tfinal is -50 and Tinitial is zero.
Total Q = q1+q2+q3+q4+q5
q1 = mass steam x specific heat steam x (Tfinal-Tinital) where Tfinal is 100 and Tinitial is 145.
q2 = heat evolved when steam at 100 C condenses to liquid at 100 C.
q2 = mass x heat vaporization
q3 = heat evolved in moving water from 100 C to zero.
q3 = mass water x specific heat water x (Tfinal-Tinitial) where T final is zero and Tinitial is 100.
q4 = heat evolved on freezing water at zero to ice at zero.
q4 = mass water x heat fusion.
q5 = heat evolved in moving ice from zero to -50.
q5 = mass ice x specific heat ice x (Tfinal-Tinitial) where Tfinal is -50 and Tinitial is zero.
Total Q = q1+q2+q3+q4+q5
Answered by
Ashley
57.8kJ
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