Asked by Kate
How many kilojoules of heat is required to completely covert 60.0 grams of water at 32.0° C to steam at 100°C?
For water:
s = 4.179 J/g °C
Hfusion = 6.01 kJ/mol
Hvap = 40.7 kJ/mol
For water:
s = 4.179 J/g °C
Hfusion = 6.01 kJ/mol
Hvap = 40.7 kJ/mol
Answers
Answered by
DrBob222
See your post above.
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