How many kilojoules of heat are absorbed when 1.00L of water is heated from 18 degrees C to 85 degrees C?

Can you please explain how to do this problem? I do not understand what to do, or understand the formula.

2 answers

q = mass x specific heat x delta T.
q = the heat absorbed.
mass = mass of the water. That is listed in the formula. 1.0 L H2O has a mass of 1000 g.
specific heat. Do you know the specific heat of water. It goes here.
delta T is the difference in temperature, in this case it is 85-18.
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