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When a force is applied to an object with mass equal to the standard kilogram, the acceleration of the mass is 3.25 m/s2. When...Asked by Sarah
When a force is applied to an object with mass equal to the standard kilogram, the acceleration of the mass is 3.25 m/s2. When the same magnitude force is applied to another object, the acceleration is 2.75 m/s2. What is the mass of the object? What would the second object's acceleration be if a force twice as large were applied to it?
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Answered by
MathMate
Sarah, you are usually better off not specifying the responder in case the latter is not available.
For the present question, Newton's second law prevails: F=ma, where F is measured in N (newton), m in kg and acceleration in m s<sup>-2</sup>.
If m1=1 kg, a=3.25 m s<sup>-2</sup>,
F = m1 * a = 1*3.25 = 3.25 N.
For the second object of mass m2,
3.25 = m2 * 2.75 m s<sup>-2</sup>
Solve for m2.
From the relation F=ma,
what would the second object's acceleration be if a force twice as large were applied to it?
For the present question, Newton's second law prevails: F=ma, where F is measured in N (newton), m in kg and acceleration in m s<sup>-2</sup>.
If m1=1 kg, a=3.25 m s<sup>-2</sup>,
F = m1 * a = 1*3.25 = 3.25 N.
For the second object of mass m2,
3.25 = m2 * 2.75 m s<sup>-2</sup>
Solve for m2.
From the relation F=ma,
what would the second object's acceleration be if a force twice as large were applied to it?
Answered by
Onyeka maryann
M=f/a=3.25/3.27=1.182kg
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