Asked by jdajaljk

A 100 N force is applied to a 50.0 kg crate resting on a level florr. The coeeficient of kinetic friction is 0.15.
a. What is the acceleration of the crate?
Answered by drwls
a = F(net)/m

F(net) = 100 N - (friction force)
Answered by jdajaljk
Fk=(0.15)50kg
Fk=7.5 N

100N-7.5N=92.5N/50kg=1.85M/s^2

thanks
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