Asked by Morgan
A force of 32.3 N is applied to a 5.87 N box resting on a table. If friction acts with a force of 2.11 N, what is the acceleration of the box?
Answers
Answered by
bobpursley
net force=mass*acceleration
32.3-2.11=5.87*a
solve for a
32.3-2.11=5.87*a
solve for a
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