Asked by Tom
What force must be applied to push a carton weighing 350 N up a 19° incline, if the coefficient of kinetic friction is 0.45? Assume the force is applied parallel to the incline and the velocity is constant. (Enter the magnitude of the force.)
Answers
Answered by
Elena
If the carton is moved at uniform velocity ma=0
F-F(fr) –mgsinα = 0
F= F(fr) +mgsinα =μmgcosα+ mgsinα =
=mg (μ•cosα + sinα)
F-F(fr) –mgsinα = 0
F= F(fr) +mgsinα =μmgcosα+ mgsinα =
=mg (μ•cosα + sinα)